An Arduino Pin on Output, stays on Output after Power Off/On. Right? So if I have a blinking output Pin 13 on Arduino (Sam3x), I can destroy it, by also doing GPIO ouput from i.mx6. Correct? Example: How to destroy pin 13: Arduino (Sam3x): blink on pin 13 Code: int led13=13; void setup() { pinMode(led13, OUTPUT); } int state = 0; void loop() { state = !state; // toggle state digitalWrite(led13, state); delay(1000); } i.Mx6 (toggle same pin, but different delay...) Code: ## in a shell echo out > /sys/class/gpio/gpio40/direction while true; do echo 1 > /sys/class/gpio/gpio40/value sleep 3 echo 0 > /sys/class/gpio/gpio40/value sleep 3 done Is it true that this will severely mess up and destroy pin 13? So my actual question: If I really want to do GPIO from i.mx6, I have to load a "dummy" arduino sketch that ensures all pins on Input. Correct??? Is there not a better way? Or any other way? "dummy" arduino sketch that ensures all pins Input. Code: void setup() { int i; for (i=0; i < 54; i++) { pinMode(i, INPUT); } } void loop() { delay(1000); } Will this work? Thanks for pointers and insight. P.
If you cut the power the Sam side should go back to default . I`m 99.9% sure this is what happens !!!! 1/ You power cycle !!!! .... REMOVE THE POWER .... and power again 2/ The Sam runs the boot loader which set all gpios to their default state. 3/ The Sam now runs the script which sets the pins via pinMode(led13, OUTPUT); etc I can`t see why not